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You can't hear the isotropy type of an orbifold
Geometry/TopologySpeaker: | Liz Stanhope, Lewis and Clark College |
Location: | 693 Kerr |
Start time: | Wed, Nov 9 2005, 4:10PM |
Riemannian orbifolds are spaces that are locally modelled on the orbit space of a Riemannian manifold under the action of a finite group of isometries. These orbifolds possess a natural Laplace operator which operates on smooth functions on the orbifold. When the orbifold is compact the eigenvalues of the Laplace operator form a sequence called the spectrum of the orbifold. As an inverse spectral geometer I ask: To what degree does the spectrum of an orbifold determine the geometry or topology of that orbifold? We will see that the spectrum does not determine the isotropy types of points in an orbifold. However, in the presence of a lower curvature bound, the spectrum does in fact provide some control on isotropy.