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Solving Differentials Problems

The following problems involve the concept of the Differential of a Function. I will introduce the Differential via it's geometric interpretation and then formulate it. For a function y=f(x) it will be shown that Differentials can be used to estimate the change of yvalues as a function of a change in x-values. We will use Differentials to solve three types of problems. Differentials will be used to

      I.) estimate the value of a numerical expression.
     II.) approximate a relatively complicated functional expression with a simpler polynomial expression.
    III.) estimate the propagation of percentage errors.

Let's begin with the graph of a function y=f(x) and consider xvalues changing from x to x+Δx, where Δx will be used to represent a small positive or negative change in x. I will refer to x as the "starting" xvalue and to x+Δx as the second xvalue. Draw a tangent line to this graph at x.

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Since xvalues change from x to x+Δx, the corresponding yvalues will change from f(x) to f(x+Δx). Define this exact change in y-values to be Δy, where Δy=f(x+Δx)f(x) We can now geometrically define this so-called Differential of f(x). We will denote the Differential by dy. It is the HEIGHT of the designated right triangle formed by x, x+Δx, and the tangent line to the graph of y=f(x) at x in the following diagram:

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Let's find a formula for dy. Recall from algebra that the SLOPE of this tangent line at x is m=riserun=dyΔx Recall also that the SLOPE of this tangent line at x is the derivative m=f(x) Setting these slopes equal to each other gives us dyΔx=f(x)

so that the Differential of Function f at x is

dy=f(x) Δx

Let's now verify that the Exact Change of  y=f(x)  is approximately equal to the Differential of  y=f(x)  for "small" Δx, i.e.,

Δydy

for small Δx. Recall that the Derivative of f at x is lim \displaystyle{ { f(x + \Delta x) - f(x) \over \Delta x } } \approx f'(x) \ \ \ \ \longrightarrow
for "small" \Delta x
\displaystyle{ { \Delta y \over \Delta x } } \approx f'(x) \ \ \ \ \longrightarrow \Delta y \approx f'(x) \ \Delta x \ \ \ \ \longrightarrow \Delta y \approx dy
for "small" \Delta x .

Here is a summary of Differentials facts.

\ \ \ \ 1. Differentials require a function, y=f(x).
\ \ \ \ 2. Differentials require two x-values, written as \ x-values: x \ \rightarrow x + \Delta x , where x is denoted as the "starting" x-value and \Delta x can be positive or negative.
\ \ \ \ 3. The Exact Change in y-values is \ \Delta y = f(x+ \Delta x)- f(x) .
\ \ \ \ 4. The Differential formula is \ dy = f'(x) \ \Delta x , where x is the "starting" x-value.
\ \ \ \ 5. We will assume that \ \Delta y \approx dy \ if \Delta x is "small."


In the list of Differentials Problems which follows, most problems are average and a few are somewhat challenging.


CATEGORY I-- Using Differentials to Estimate the Value of a Numerical Expression



CATEGORY II-- Using Differentials to Approximate a Relatively Complicated Functional Expression with a Simpler Polynomial Expression



CATEGORY II-- Using Differentials to Approximate the Percentage Errors

For the following problems we will refer to |\Delta x| as the "absolute error in x and to |\Delta y| as the "absolute error in y. We will define \displaystyle{ |\Delta x| \over x } to be the "absolute percentage error in x" and \displaystyle{ |\Delta y| \over y } to be the "absolute percentage error in y". For example, if \Delta x= -0.4 and x=20, then the absolute percentage error in x is \displaystyle{ |-0.4| \over 20 }= { 0.4 \over 20 } = { 0.4 \over 20 }{ 5 \over 5} = { 2 \over 100 } = 2\%

CATEGORY III-- Miscellaneous Differential Problems




Click HERE to return to the original list of various types of calculus problems.


Your comments and suggestions are welcome. Please e-mail any correspondence to Duane Kouba by clicking on the following address :

kouba@math.ucdavis.edu


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Duane Kouba ... October 24, 2019